The diagram shows a 200V short shunt compound generator. What is the voltage across the series field resistance?
- 10V
- 6V
- 30V
Explanation from PART66Online
In a short shunt compound generator the shunt field is connected across the armature only, and the series field is in series with the load. In the diagram the 100 ohm resistor is the shunt field, the 0.04 ohm resistor in the armature branch is the armature resistance, and the 0.06 ohm resistor in the line to the load is the series field. The series field therefore carries the full 100 A load current, so V = I x R = 100 x 0.06 = 6 V. The 10 V option adds the armature resistance as well (100 x 0.1).
B
bennguli asked · 10 May 2017
explain
Community Comments (2)
H
huly
23 Feb 2018
The voltage U=I*R, the current through the parallel resistor on the right is 100A so the same through 0.06ohm resistor because they are series. Then U=100*0.06= 6V
V
vale
21 Sep 2020
still I don't understand..
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