The true power developed in this circuit is
- 20W.
- 50W.
- 12W.
Shawez asking:
anyone please explain
Community Comments (5)
D
dimky Posts: 511 16.02.2015 / 21:47
True power is only in the resistor = I^2 * R = 2x2x3 = 12W
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ggmu Posts: 4 28.07.2015 / 19:25
How abt P=IV = 2 * 10 = 20w ? Guide me thanks :)
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dimky Posts: 511 31.07.2015 / 06:29
Hello ggmu.
True power in this circuit is only in resistor.
So you have to calculate voltage drop across resistor and then use your formula, or you can use formula provided in my first post. Hope that helps.
True power in this circuit is only in resistor.
So you have to calculate voltage drop across resistor and then use your formula, or you can use formula provided in my first post. Hope that helps.
D
dimky Posts: 511 31.07.2015 / 06:31
And please read about power here: http://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
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ggmu Posts: 4 08.08.2015 / 14:38
Thank u. Appretiate it :)
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