The true power developed in this circuit is
- 20W.
- 50W.
- 12W.
Explanation from PART66Online
True power is the power dissipated in the resistance only: P = I squared x R = 2 x 2 x 3 = 12 W. The inductor stores energy and returns it each cycle, so it dissipates none. The 20 W option is V x I = 10 x 2, which is the apparent power (20 VA), not the true power. Check: Z = square root of (3 squared + 4 squared) = 5 ohms, and 10 V / 5 ohms = 2 A, as shown.
S
Shawez asked · 16 Feb 2015
anyone please explain
Community Comments (5)
P
PART66Online
16 Feb 2015
True power is only in the resistor = I^2 * R = 2x2x3 = 12W
G
ggmu
28 Jul 2015
How abt P=IV = 2 * 10 = 20w ? Guide me thanks :)
P
PART66Online
31 Jul 2015
Hello ggmu.
True power in this circuit is only in resistor.
So you have to calculate voltage drop across resistor and then use your formula, or you can use formula provided in my first post. Hope that helps.
True power in this circuit is only in resistor.
So you have to calculate voltage drop across resistor and then use your formula, or you can use formula provided in my first post. Hope that helps.
P
PART66Online
31 Jul 2015
And please read about power here: allaboutcircuits.com/textbook/alterna...
G
ggmu
8 Aug 2015
Thank u. Appretiate it :)
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