The circuit shown is at resonance. If the value of the inductance is trebled, the impedance will
- stay the same.
- treble.
- reduce by one-third.
roja90 asking:
parallel circuit dynamic impedance Z=L/CR. so inductance trebled impedance also treble.
is it correct ?
Community Comments (4)
D
dimky Posts: 514 08.03.2012 / 17:03
Hello.
Here is explanation from question bank:
At resonance, the impedance of the L-C pair is maximum. If you upset the L-C balance you destroy the resonance. The impedance of the L-C pair will then reduce, reducing the impedance of the circuit as a whole (although 'by one-third' is debatable).
Here is explanation from question bank:
At resonance, the impedance of the L-C pair is maximum. If you upset the L-C balance you destroy the resonance. The impedance of the L-C pair will then reduce, reducing the impedance of the circuit as a whole (although 'by one-third' is debatable).
S
sasna Posts: 20 27.07.2013 / 12:37
so if the inductance reduced the answer will be the same????
S
sasna Posts: 20 27.07.2013 / 12:43
for resonance, if inductance is 3 times more the capacitance has to be 3 times more, to get this three times capacitance we can say impedance reduced by one third...
S
st_eagle Posts: 2 02.06.2016 / 06:55
Still doesn't make sense...
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