The circuit shown is at resonance. If the value of the inductance is trebled, the impedance will
- stay the same.
- treble.
- reduce.
Explanation from PART66Online
At resonance a parallel R-L-C circuit presents its maximum impedance, because the inductive and capacitive branch currents cancel and only the resistive branch draws current from the supply. Trebling the inductance destroys that balance, so the two branch currents no longer cancel, the supply current rises and the impedance falls. Moving L or C away from resonance in either direction can only reduce it.
R
roja90 asked · 8 Mar 2012
parallel circuit dynamic impedance Z=L/CR. so inductance trebled impedance also treble.
is it correct ?
Community Comments (4)
P
PART66Online
8 Mar 2012
Hello.
Here is explanation from question bank:
At resonance, the impedance of the L-C pair is maximum. If you upset the L-C balance you destroy the resonance. The impedance of the L-C pair will then reduce, reducing the impedance of the circuit as a whole (although 'by one-third' is debatable).
Here is explanation from question bank:
At resonance, the impedance of the L-C pair is maximum. If you upset the L-C balance you destroy the resonance. The impedance of the L-C pair will then reduce, reducing the impedance of the circuit as a whole (although 'by one-third' is debatable).
S
sasna
27 Jul 2013
so if the inductance reduced the answer will be the same????
S
sasna
27 Jul 2013
for resonance, if inductance is 3 times more the capacitance has to be 3 times more, to get this three times capacitance we can say impedance reduced by one third...
S
st_eagle
2 Jun 2016
Still doesn't make sense...
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