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In the circuit shown, the power developed across the 10 kilo ohm resistor is

Diagram for question: In the circuit shown, the power developed across the 10 kilo ohm resistor is
  • 250 mW.
  • 250 W.
  • 50 mW.

Explanation from PART66Online

The resistors are in series, so the total is 10 + 30 = 40 kilohms and the current is 200 / 40,000 = 5 mA. The power in the 10 kilohm resistor is P = I x I x R = 0.005 x 0.005 x 10,000 = 0.25 W = 250 mW. Cross-check: the 10 kilohm resistor drops a quarter of the supply (50 V), and P = V x I = 50 x 0.005 = 0.25 W. The 250 W option treats 5 mA as 5 A and 10 kilohms as 10 ohms.

N

niket8989 asked · 18 Jun 2012

Please Explain 250mW as answer

Community Comments (2)

M
MridulDev 18 Jun 2012
FIRST FIND OUT THE TOTAL CURRENT IN THE CIRCUIT. USING FORMULA I=V/R
(R is total resistance of circuit)

NOW USE power formula ie, I*I*R
(in this step put the value of R=10K ohm). Tada job done.
D
disho251 18 Apr 2024
how is it mW

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