The picture shows a torque wrench with an extension. To apply a torque of 350 lb.in. the reading on the dial should be
- 245 lb.in.
- 280 lb.in.
- 350 lb.in.
Explanation from PART66Online
An extension that lengthens the wrench in line multiplies the torque applied at the fastener: fastener torque = dial reading x (L + E) / L, where L is the wrench length (12 in) and E the extension (3 in). So the dial reading needed is 350 x 12 / (12 + 3) = 350 x 12 / 15 = 280 lb.in. Setting 350 lb.in on the dial would over-torque the fastener to 350 x 15 / 12 = 437.5 lb.in.
O
omarali asked · 2 Oct 2024
why?
Community Comments (2)
M
mahmoud_a380
25 Oct 2024
M1 = M2 x L1 / L2
where:
M1 is the torque setting of the wrench (what you set the wrench to)
M2 is the actual torque applied to the nut (what you want to achieve)
L1 is the normal length of the wrench (without the extension)
L2 is the extended length of the wrench (length of the wrench + length of the extension)
= 350*15/12 = 280
where:
M1 is the torque setting of the wrench (what you set the wrench to)
M2 is the actual torque applied to the nut (what you want to achieve)
L1 is the normal length of the wrench (without the extension)
L2 is the extended length of the wrench (length of the wrench + length of the extension)
= 350*15/12 = 280
O
omarali
30 Oct 2024
شكرا
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