The oscillation produced by a pendulum 2500mm long has a periodic time of
- 6 seconds.
- 3 seconds.
- 9 seconds.
Explanation from PART66Online
With length 2500 mm = 2.5 m, the period is T = 2 pi times the square root of L/g = 2 pi x square root of (2.5 / 9.81), which is about 2 pi x 0.505 = 3.17 s, rounded to 3 seconds. Period depends only on length and gravity, not the bob mass.
A
Arunkumar222 asked · 3 Dec 2014
Kindly explain with formula
Community Comments (4)
P
PART66Online
3 Dec 2014
T = 2xπ√L/g = √2.5/10 = 6 * √0.25 = 6 * 0.5 = 3
M
Matas24
27 Feb 2018
whaat?
M
Matas24
4 Mar 2018
Sry, my browser didnt load the formula correctly
M
Matas24
4 Mar 2018
t=2*pi*sq.root(2,5/9,81)=3,14s
Please Sign In to post a comment.