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Module 2. Physics

The tension in the cable of a crane is 2500 N and it lifts a load through 50m, what is the work done on the load?

  • 2.50 * 10^4 J
  • 1.25 * 10^5 J
  • 5.00 * 10^3 J

Explanation

Work done equals force times distance moved in the direction of the force: 2500 N x 50 m = 125,000 J, or 1.25 x 10 to the fifth joules. The cable tension is the lifting force, so the full distance is used in the calculation.

boherbue asking:

Please explain.

Community Comments (3)

M
MridulDev Posts: 48 23.05.2013 / 12:39
W.d = Force * Distance,
where F is in Newton
D is in Meters
And resulting product is in joules.
Work on that
T
trap2307 Posts: 43 23.05.2013 / 21:30
Hello!
2500 * 50 = 125000
1.25 * 10^5 = 125000
N*m=J
http://en.wikipedia.org/wiki/Joule
B
boherbue Posts: 1 26.05.2013 / 22:01
cheers

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