The tension in the cable of a crane is 2500 N and it lifts a load through 50m, what is the work done on the load?
- 2.50 * 10^4 J
- 1.25 * 10^5 J
- 5.00 * 10^3 J
Explanation
Work done equals force times distance moved in the direction of the force: 2500 N x 50 m = 125,000 J, or 1.25 x 10 to the fifth joules. The cable tension is the lifting force, so the full distance is used in the calculation.
boherbue asking:
Please explain.
Community Comments (3)
where F is in Newton
D is in Meters
And resulting product is in joules.
Work on that
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