The tension in the cable of a crane is 2500 N and it lifts a load through 50m, what is the work done on the load?
- 1.25 * 10^5 J
- 2.50 * 10^4 J
- 5.00 * 10^3 J
Explanation from PART66Online
Work done equals force times distance moved in the direction of the force: 2500 N x 50 m = 125,000 J, or 1.25 x 10 to the fifth joules. The cable tension is the lifting force, so the full distance is used in the calculation.
B
boherbue asked · 22 May 2013
Please explain.
Community Comments (3)
M
MridulDev
23 May 2013
W.d = Force * Distance,
where F is in Newton
D is in Meters
And resulting product is in joules.
Work on that
where F is in Newton
D is in Meters
And resulting product is in joules.
Work on that
T
trap2307
23 May 2013
B
boherbue
26 May 2013
cheers
Please Sign In to post a comment.
More discussions in 2. Physics
- The work done in lifting a mass of 2000 kg vertically to a height of 40 metres is
- The work done in lifting a mass of 2000 kg vertically to a height of 40 metres is
- How would you work out the work done by a machine assuming it is 100% efficient?
- Ignoring friction, if you let an object slide down a slope, at the bottom
- A force of 15N is needed to move a body of mass 30kg along a footpath with uniform velocity. Find the coefficient of dynamic friction.(take g as 10m/s/s).
- A mass of 400kg moves 27 metres with a force of 54N. What is the work produced?