An inductor has 1,000 turns of wire and a cross sectional area of 0.001m2. If the core has a permeability of 0.000,001 and the coil is 0.1m. What is the value of the inductor?
- 100microH.
- 100mH.
- 10mH.
Explanation from PART66Online
Inductance of a coil is L = micro*N^2*A / l. Substituting: (0.000001 * 1000^2 * 0.001) / 0.1 = (1e-6 * 1e6 * 0.001) / 0.1 = 0.001 / 0.1 = 0.01H = 10mH. The result scales with the square of turns and the core permeability, and inversely with the magnetic path length.
S
sasna asked · 27 Jan 2014
How to solve
Community Comments (2)
P
PART66Online
27 Jan 2014
Hey.
L = (μr * N^2 * A) / l = 0.000001 * 1000^2 * 0.001 / 0.1 = 0.01H = 10mH
μr - permeability
N - turns
A - x-sectional area
l - lenght
L = (μr * N^2 * A) / l = 0.000001 * 1000^2 * 0.001 / 0.1 = 0.01H = 10mH
μr - permeability
N - turns
A - x-sectional area
l - lenght
S
sasna
28 Jan 2014
Thanx
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