An aircraft weighing 6400 pounds lands at a speed of 10 ft/Sec and stops in 10 Seconds. What force was generated by the brakets (asuming gravity as 32 ft/sec).
- -400 Lbs.
- -200 Lbs.
- -640 Lbs.
Explanation from PART66Online
The aircraft mass is weight / g = 6400 / 32 = 200 slugs. Decelerating from 10 ft/s to rest in 10 s gives a = -1 ft/s squared, so braking force = m x a = 200 x (-1) = -200 lb. The negative sign shows the force opposes the motion.
R
ranz130 asked · 19 Aug 2013
still not get it,can somebody explain it.
Community Comments (1)
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PART66Online
19 Aug 2013
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