The oscillation produced by a pendulum 2500mm long has a periodic time of
- 6 seconds.
- 3 seconds.
- 9 seconds.
Explanation
With length 2500 mm = 2.5 m, the period is T = 2 pi times the square root of L/g = 2 pi x square root of (2.5 / 9.81), which is about 2 pi x 0.505 = 3.17 s, rounded to 3 seconds. Period depends only on length and gravity, not the bob mass.
romeshkunder asking:
please explain
Community Comments (1)
R
rajib Posts: 8 29.08.2013 / 14:48
T=2*pi(L/G)^1/2
for your further reference go this link http://hyperphysics.phy-astr.gsu.edu/hbase/pend.html#c2
for your further reference go this link http://hyperphysics.phy-astr.gsu.edu/hbase/pend.html#c2
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