A right angled triangle has sides 6cm, 8cm and 10 cm. What is the sine of the angle between the 8cm side and the 10 cm side?
- 0.6
- 0.75
- 0.8
Explanation
The triangle is right-angled with the 10 cm side as the hypotenuse. The angle between the 8 cm and 10 cm sides has the 6 cm side opposite it, so its sine is opposite over hypotenuse = 6/10 = 0.6. The value 0.8 would be the cosine of this same angle (8/10).
Wisedavy asking:
How do i go about it
Community Comments (2)
R
riccio_ruffo_44 Posts: 2 03.12.2025 / 10:58
you need to divide the opposite side/ adiacent side (6/10=0.6)
R
riccio_ruffo_44 Posts: 2 03.12.2025 / 10:58
you need to divide the opposite side/ adiacent side (6/10=0.6)
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