Evaluate 2x^2 * z^2 * (3x - z^2 ) =
- 6x^3 * z^2 - 2x^2 * z^4
- 6x^2 * z^2 - 2x^2 * z^2
- 6x^2 * z^2 + 3x - z^2
Richiegeee asking:
Can someone please explain?
Community Comments (1)
S
Sina Posts: 2 24.02.2015 / 20:05
(2x)^2 * (z)^2 * (3x - z^2 ) =
4x^2 * z^2 * (3x-z^2) = {(4x^2 * z^2)*(3x) - (4x^2 * z^2)*(-z^2)} =
12x^3 * z^2 - 4x^2 * z4
Thus; (12x^3*z^2 - 4x^2*z4) / 2 ==> 6x^3 * z^2 - 2x^2 * z^4
4x^2 * z^2 * (3x-z^2) = {(4x^2 * z^2)*(3x) - (4x^2 * z^2)*(-z^2)} =
12x^3 * z^2 - 4x^2 * z4
Thus; (12x^3*z^2 - 4x^2*z4) / 2 ==> 6x^3 * z^2 - 2x^2 * z^4
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