A plate 10 inches by 5 inches is to be riveted with 3 rows of rivets, with the normal 4D rivet spacing and 2 D edge distance. The rivets are AN460AD4-6. How many rivets are required?
- 60.
- 52.
- 56.
Explanation
Along the 10 inch length, 2D edge distance at each end (D=1/8 in for an AD-4 rivet, so 1/4 in total at each end) leaves 9.5 in; at 4D (1/2 in) pitch this gives 19 spaces, hence 20 rivets per row. With 3 rows that is 3 x 20 = 60 rivets.
airmech932 asking:
How?
Community Comments (2)
If it is to be riveted along the 10 inch length, subtract the edge distances (2 * 1/4 inch) = 9 and a 1/2 inches.
4D = 1/2 inch. You can fit 20 rivets in 9 1/2 inches. 3 * 20 = 60
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