The earth lead of a 24 V equipment is 0.5 ohm resistance and carries 80 A. How much power does it dissipate?
- 1.92 kW.
- 1.152 kW.
- 3.2 kW.
Explanation from PART66Online
Power lost in the lead depends on its current and resistance, not the 24 V supply: P = I squared x R = 80 squared x 0.5 = 6400 x 0.5 = 3200 W = 3.2 kW. The 24 V value is a distractor, since the relevant voltage is the small drop across the lead itself.
A
arifadli8 asked · 9 Jan 2014
P=VI
so p=24 x 80=1.92 kw
????
Community Comments (1)
M
manzagip
11 Mar 2014
Hi, P=R*I^2 -----> 80*80*0.5 = 6400/2 = 3.2 kW
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