What is the power dissipated in a 500 ohm resistor with a 3A flow?
- 4.5 kW.
- 1.5 kW.
- 750 kW.
Explanation from PART66Online
With current and resistance known, use P = I squared x R = 3 squared x 500 = 9 x 500 = 4500 W = 4.5 kW. The 1.5 kW answer comes from using P = I x R rather than the correct I squared term.
S
Sbrangy asked · 18 Mar 2021
How?
Community Comments (2)
S
s.radovanovic
19 May 2022
P=I*E
E=I*R
R=500OHM
I=3A
P=4500W=4.5KW
E=I*R
R=500OHM
I=3A
P=4500W=4.5KW
W
Willy79
4 Dec 2025
P = (I * I) * R
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