The centre of gravity of an aircraft is adjusted by two weights, 10 kg and 5 ckg plaed 4m and 2 m aft of the c of g. To what position must a 20 kg weight be added to balance the c of g?
- 2.5m.
- 1.5m.
- 3.0m.
Explanation from PART66Online
The two existing weights produce a moment about the c of g of (10 kg x 4 m) + (5 kg x 2 m) = 50 kg.m aft. To balance, the 20 kg weight must create an equal and opposite moment, so its distance is 50 divided by 20, giving 2.5 m on the forward side.
A
AndreaFrasconi asked · 20 Mar 2023
Why
Community Comments (3)
R
redwalt
25 Mar 2023
Because (10×4)+(5×2) = 20×2.5
R
redwalt
25 Mar 2023
Actually it was (10×9.81×4)+(5×9.81×2) = 20×9.81×2.5 , but it works either way
M
mano
11 Apr 2024
Weight arm momentum
10kg 4m 40
5kg 2m 10
Total aft 50 then
20kg 2.5m 50
10kg 4m 40
5kg 2m 10
Total aft 50 then
20kg 2.5m 50
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