A 24V battery has an internal resistance of 1 ohm. When connected to a load, 12 amps flows. The value of the load is
- 12 ohms.
- 1/2 ohm.
- 1 ohm.
Explanation from PART66Online
The total circuit resistance is V / I = 24 V / 12 A = 2 ohms. Subtracting the 1-ohm internal resistance leaves the load at 2 - 1 = 1 ohm, since the internal and load resistances are in series.
R
Richiegeee asked · 4 Dec 2015
help?
Community Comments (1)
P
PART66Online
5 Dec 2015
Total R = V/I = 24/12 = 2 ohms.
Subtract the internal resistance to get the external resistance (i.e. the load).
Subtract the internal resistance to get the external resistance (i.e. the load).
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