What is the equivalent of this gate?
- = (NOT-A + NOT-B)
- = (NOT-A . NOT-B)
- = NOT-(A.B) + (A)
sasna asking:
correct the answer.....
Community Comments (7)
R
rajib Posts: 8 26.08.2013 / 06:48
Answer is correct, please go through De Morgan's laws,
for reference :
http://www2.nau.edu/~sh295/EE110/deMorganproof.html
for reference :
http://www2.nau.edu/~sh295/EE110/deMorganproof.html
S
sasna Posts: 20 27.08.2013 / 00:30
why not (A.B)NOT...???
D
dimky Posts: 511 01.09.2013 / 10:45
Draw truth tables for all answers and compare them with truth table of NAND gate.
K
karmendra Posts: 1 30.05.2017 / 22:43
Why not (A.B)NOT is a right answer. It's straight forward from the drawing. AND gate with a output inverted is (A.B)NOT gate
S
Shenoy Posts: 1 30.08.2019 / 15:37
i agree with karmendra
S
Sokeros Posts: 13 04.03.2020 / 11:22
I agree too. I think answer c is the correct answer.
M
Matteo Passatempi Posts: 1 13.04.2023 / 12:48
the answer A is the correct boolean simbology for the drawing but it's not the equivalent one, so the correct answer is the A
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