What is the equivalent of this gate?
- = (NOT-A + NOT-B)
- = (NOT-A . NOT-B)
- = NOT-(A.B) + (A)
Explanation from PART66Online
The symbol is an AND gate with an inversion bubble on its output: a NAND gate, X = NOT-(A.B). By De Morgan's theorem, inverting an AND is the same as ORing the inverted inputs: NOT-(A.B) = NOT-A + NOT-B. Check with A = B = 1: the NAND output is 0, and NOT-A + NOT-B = 0 + 0 = 0. NOT-A . NOT-B is the NOR function, which is 1 only when both inputs are 0.
S
sasna asked · 25 Aug 2013
correct the answer.....
Community Comments (7)
R
rajib
26 Aug 2013
Answer is correct, please go through De Morgan's laws,
for reference :
www2.nau.edu/~sh295/EE110/deMorganpro...
for reference :
www2.nau.edu/~sh295/EE110/deMorganpro...
S
sasna
26 Aug 2013
why not (A.B)NOT...???
P
PART66Online
1 Sep 2013
Draw truth tables for all answers and compare them with truth table of NAND gate.
K
karmendra
30 May 2017
Why not (A.B)NOT is a right answer. It's straight forward from the drawing. AND gate with a output inverted is (A.B)NOT gate
S
Shenoy
30 Aug 2019
i agree with karmendra
S
Sokeros
4 Mar 2020
I agree too. I think answer c is the correct answer.
M
Matteo Passatempi
13 Apr 2023
the answer A is the correct boolean simbology for the drawing but it's not the equivalent one, so the correct answer is the A
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