A near perfect 4:1 step up transformer has it`s primary connected to 120VAC, if the secondary is connected to a load with 1600 ohms resistance, what is the current in the primary?
- 0.3 amps.
- 1 amp.
- 1.2 amps.
Explanation
The 4:1 step-up raises 120 V to 480 V on the secondary, so the secondary current is 480/1600 = 0.3 A and the load power is 480 x 0.3 = 144 W. In a near-perfect transformer the primary power matches, so the primary current is 144 W / 120 V = 1.2 A. Equivalently, primary current is four times the 0.3 A secondary current.
wenyang asking:
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