If an AC sine wave has an RMS value of 5V its peak value is
- 6.37 V.
- 7.07 V.
- 14.14 V.
Explanation from PART66Online
For a sinusoidal AC waveform the peak value equals the RMS value multiplied by the square root of 2. So 5 V x 1.414 gives roughly 7.07 V. The 6.37 V option is the figure you would get from the average-rectified relationship, not the peak, which is why it is wrong.
S
Smyjer asked · 27 Nov 2021
Peak value is 1.414 the effective value
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