A conductor with a positive Q (charge) of 4C has 12.56 x 1018 electrons added to it. It will have a Q =
- 6.
- 2.
- 0.
Explanation
Each electron carries about 1.6 x 10^-19 coulombs, so 12.56 x 10^18 electrons add roughly 2 C of negative charge. Subtracting this from the original positive charge of 4 C leaves a net charge of about +2 C on the conductor.
Richiegeee asking:
help?
Community Comments (3)
D
dimky Posts: 514 08.12.2015 / 21:52
Charge of one coulomb equals 6.28 * 1018. So that means what you have added 2 coulombs. Total will be 6.
R
Richiegeee Posts: 7 09.12.2015 / 14:18
THANKS
C
Corne Posts: 1 21.04.2020 / 15:21
If you have a positive Q, and you add electrons, wont it be 4C - 2C?
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