A conductor with a positive Q (charge) of 4 C has 12.56 x 10^18 electrons added to it. It will have a Q =
- +6 C
- +2 C
- 0 C
Explanation from PART66Online
Each electron carries about 1.6 x 10^-19 coulombs, so 12.56 x 10^18 electrons add roughly 2 C of negative charge. Subtracting this from the original positive charge of 4 C leaves a net charge of about +2 C on the conductor.
Richiegeee asked · 8 Dec 2015
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