A 3, 5 and 2 ohms resistance is connected in series with a 10 V battery. The voltage across the 2 ohms resistor is
- 2 V.
- 10V.
- 4 V.
Explanation
The series resistances total 3 + 5 + 2 = 10 ohms, so the current is 10 V / 10 ohms = 1 A. The voltage across the 2-ohm resistor is then I x R = 1 A x 2 ohms = 2 V.
Jacopo asking:
Someone could explain pls?
Community Comments (1)
J
JPRASAD2015 Posts: 2 02.02.2015 / 01:16
I=V/R=10/10=1A
Thus V across 2 ohm, V=IR, V=1*2=2V
Thus V across 2 ohm, V=IR, V=1*2=2V
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