What is the phase difference in a circuit with 100V, drawing 0.5 amps, consuming 50 Watts?
- 0degrees.
- 45degrees.
- 90degrees.
Explanation from PART66Online
Apparent power S = V*I = 100*0.5 = 50 VA, while true power is 50 W, so power factor = P/S = 50/50 = 1. A power factor of unity means costheta = 1, giving a phase difference of 0 degrees - the circuit behaves resistively with current and voltage in phase.
W
watzz asked · 9 Oct 2014
How to do this?
Community Comments (3)
S
sta8ispolemi
22 Oct 2014
POWER(watts)=VxI
--> 50watts=100Vx0.5amps
--> 50watts=50watts
--> 50watts=100Vx0.5amps
--> 50watts=50watts
S
sta8ispolemi
22 Oct 2014
POWER(watts)=VxI
--> 50watts=100Vx0.5amps
--> 50watts=50watts
--> 50watts=100Vx0.5amps
--> 50watts=50watts
W
watzz
22 Oct 2014
Thank you!
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