Transformer copper loss on full load is 220 Watts. On half load the loss will be
- 440 Watts.
- 110 Watts.
- 55 Watts.
Explanation
Copper loss is I-squared-R, so it varies with the square of the load current. At half load the current is halved, so the loss falls to one quarter of its full-load value: 220/4 = 55 W. The 110 W answer incorrectly assumes the loss halves linearly with load.
arifadli8 asking:
How???
Community Comments (1)
D
dimky Posts: 514 31.12.2013 / 14:55
Since copper loss is given by I2R, if the load doubles, the copper loss will quadruple. So it must have been 55 Watts on half load to be 220 Watts on full load.
Please Sign In to post a comment.