In an inductive resistive circuit, 1 amp flows from a supply of 100V dissipating 50 Watts of power. The phase angle is
- 60degrees.
- 90degrees.
- 45degrees.
Explanation from PART66Online
True power is P = V x I x cos(theta), so cos(theta) = 50 / (100 x 1) = 0.5. The angle whose cosine is 0.5 is 60 degrees, giving the phase angle. A 90-degree angle would dissipate no power, and 45 degrees would correspond to a power factor of about 0.707.
A
arifadli8 asked · 29 Dec 2013
Please teach me...
Community Comments (1)
P
PART66Online
31 Dec 2013
Hey!
Apparent power = amps * volts = 1 * 100 = 100VA
True power = 50W
Power Factor = TP/AP = 50/100 = 0.5
PF = COSINE of phase angle.
0.5 = COSINE of phase angle.
PA = arccos(0.5) = 60.
Apparent power = amps * volts = 1 * 100 = 100VA
True power = 50W
Power Factor = TP/AP = 50/100 = 0.5
PF = COSINE of phase angle.
0.5 = COSINE of phase angle.
PA = arccos(0.5) = 60.
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