If the cross-sectional area of a conductor is doubled, with voltage constant, the current will
- remain constant.
- double.
- halve.
Explanation
Resistance is inversely proportional to cross-sectional area, so doubling the area halves the resistance. With voltage held constant, Ohm's law then makes the current double, since halving resistance doubles the current.
iskandarazli asking:
anybody can help me explain about this?
Community Comments (1)
D
dimky Posts: 514 22.02.2012 / 14:45
Hey!
Formula for resistance of conductor is: R = (r * L) / A
Where r = resistivity of conductor (http://hyperphysics.phy-astr.gsu.edu/hbase/tables/rstiv.html)
L = lenght
A = cross section area
Then apply ohms law: I = U / R
Formula for resistance of conductor is: R = (r * L) / A
Where r = resistivity of conductor (http://hyperphysics.phy-astr.gsu.edu/hbase/tables/rstiv.html)
L = lenght
A = cross section area
Then apply ohms law: I = U / R
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