Given that 1 cubic foot of water weighs 62.4 lbs and the specific gravity of fuel is 0.81, what is the weight of 10 cubic foot of fuel?
- 402.8 lbs.
- 505.4 lbs.
- 624.0 lbs.
Explanation
Fuel weight equals water weight times specific gravity times volume. One cubic foot of water is 62.4 lb, so one cubic foot of fuel is 62.4 x 0.81 = 50.544 lb, and ten cubic feet weigh 505.44 lb, rounding to 505.4 lb. The 624 lb option ignores the 0.81 specific gravity.
arifadli8 asking:
how to solve its?
Community Comments (3)
D
dimky Posts: 514 06.09.2013 / 18:43
62.4 * 10 * 0.81 = 505.4
N
nkris10 Posts: 2 09.03.2017 / 12:08
why?
A
avionics Posts: 9 09.03.2017 / 14:32
1 cubic foot of water = 62.4 lbws
1cubic foot of fuel = x lbs
10 cubic foot of fuel = 10x lbs
density of water = m/V = 62.4lbs/1 cubic foot of water.
density of fuel = x /1 cubic foot of fuel ,
but since we want to know what is mass for a 10 cubic of fuel
density of fuel = 10x / 10 cubic foot of fuel
we know s.g = density of fuel/density of water
hence s.g = (10x/10)/(62.4/1) = 0.81
10x = 0.81*62.4*10
= 505.4
= weigh of 10cubic foot of fuel
1cubic foot of fuel = x lbs
10 cubic foot of fuel = 10x lbs
density of water = m/V = 62.4lbs/1 cubic foot of water.
density of fuel = x /1 cubic foot of fuel ,
but since we want to know what is mass for a 10 cubic of fuel
density of fuel = 10x / 10 cubic foot of fuel
we know s.g = density of fuel/density of water
hence s.g = (10x/10)/(62.4/1) = 0.81
10x = 0.81*62.4*10
= 505.4
= weigh of 10cubic foot of fuel
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