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Module 2. Physics

A radar rotates 1 revolution each 30 seconds and uses 10J of energy each revolution. How many joules does it use in a day?

  • 28.8 kJ.
  • 14.4 kJ.
  • 57.6 kJ.

Explanation

At one revolution every 30 seconds, the radar completes 2880 revolutions in a day (86,400 s / 30). Multiplying by the 10 J used per revolution gives 28,800 J, or 28.8 kJ. Energy used is simply the energy per cycle times the number of cycles in the period.

arifadli8 asking:

how to solve its??

Community Comments (2)

T
trap2307 Posts: 43 04.09.2013 / 21:29
Hello!
2 revolution per 1 minut. 20J per 1 min. 60 min in 1 hour. 24 hours in day.
T
trap2307 Posts: 43 04.09.2013 / 21:35
20*60*24=28800J = 28.8 kJ

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