A radar rotates 1 revolution each 30 seconds and uses 10J of energy each revolution. How many joules does it use in a day?
- 28.8 kJ.
- 14.4 kJ.
- 57.6 kJ.
Explanation from PART66Online
At one revolution every 30 seconds, the radar completes 2880 revolutions in a day (86,400 s / 30). Multiplying by the 10 J used per revolution gives 28,800 J, or 28.8 kJ. Energy used is simply the energy per cycle times the number of cycles in the period.
A
arifadli8 asked · 4 Sep 2013
how to solve its??
Community Comments (2)
T
trap2307
4 Sep 2013
Hello!
2 revolution per 1 minut. 20J per 1 min. 60 min in 1 hour. 24 hours in day.
2 revolution per 1 minut. 20J per 1 min. 60 min in 1 hour. 24 hours in day.
T
trap2307
4 Sep 2013
20*60*24=28800J = 28.8 kJ
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