An aircraft weighing 6400 pounds lands at a speed of 10 ft/Sec and stops in 10 Seconds. What force was generated by the brakets (asuming gravity as 32 ft/sec).
- -400 Lbs.
- -200 Lbs.
- -640 Lbs.
Explanation
The aircraft mass is weight / g = 6400 / 32 = 200 slugs. Decelerating from 10 ft/s to rest in 10 s gives a = -1 ft/s squared, so braking force = m x a = 200 x (-1) = -200 lb. The negative sign shows the force opposes the motion.
Rajaram12 asking:
Plz solve this
Community Comments (3)
D
dimky Posts: 514 24.06.2013 / 16:56
F = m * a
Where:
F - Force
m - Mass
a - Acceleration
m = 6400 / 32 = 200
a = 10 / 10 = -1 (negative because deceleration)
F = 200 * (-1) = 200
Where:
F - Force
m - Mass
a - Acceleration
m = 6400 / 32 = 200
a = 10 / 10 = -1 (negative because deceleration)
F = 200 * (-1) = 200
R
ravi.0813 Posts: 1 02.12.2014 / 04:07
Actually unit of weight is Newton(N) not pound. So aircraft weight should be 6400 Newtons.
J
Jordi Posts: 198 14.06.2020 / 17:07
yeah i agree with Ravi i think this question shoud change answers because when we say weight we mean the force which is given by W=m*g and mass which is found by the W=m*g.Can you please change it.
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