The emitter, base and collector currents in a common emitter circuit, follow ohm"s and kirchoff"s law, which is
- Ie = Ic - Ib.
- Ib = Ie + Ic.
- Ie = Ib + Ic.
Explanation
By Kirchhoff's current law the current entering a transistor must equal the current leaving it, so the emitter current equals the sum of the base and collector currents: Ie = Ib + Ic. Since the base current is very small, the emitter and collector currents are nearly equal, but the emitter current is always the largest of the three.
seangoodwin66 asking:
Please write your comment here.the ans is wrong its 1b+1e-1c
Community Comments (1)
K
ko112094 Posts: 1 18.09.2012 / 01:35
the ans is correct
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