A body dropped from 10 m will hit the ground in
- 2.83 seconds.
- 0.71 seconds.
- 1.41 seconds.
Explanation
For a body dropped from rest, t = the square root of (2h / g) = the square root of (2 x 10 / 9.81) = the square root of 2.04 = about 1.41 seconds. The 2.83 s answer doubles the time, and 0.71 s halves it, both from misapplying the square-root relationship.
bigbear asking:
PLEASE EXPLAIN FOR ME?? THINKS
Community Comments (3)
K
karol288 Posts: 7 18.01.2025 / 00:45
The time of free fall can be calculated:
t=square root(2h/g)
g=10 m/s^2
t = sq.root(2*10/10) = sq.root(2) = 1,41 seconds
t=square root(2h/g)
g=10 m/s^2
t = sq.root(2*10/10) = sq.root(2) = 1,41 seconds
E
Eddz25 Posts: 7 23.05.2025 / 03:38
use velocity formula, s-ut + 1/2 at(2)
E
Eddz25 Posts: 7 23.05.2025 / 03:39
s=ut + 1/2 at(2)
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