A body dropped from 10 m will hit the ground in
- 2.83 seconds.
- 0.71 seconds.
- 1.41 seconds.
Explanation from PART66Online
For a body dropped from rest, t = the square root of (2h / g). Taking g as 10 m/s2 gives t = the square root of (2 x 10 / 10) = the square root of 2 = 1.41 seconds. Using 9.81 m/s2 instead gives 1.43 seconds, so 1.41 is the value expected here. The 2.83 s answer doubles the time and 0.71 s halves it.
B
bigbear asked · 24 Jul 2024
PLEASE EXPLAIN FOR ME?? THINKS
Community Comments (3)
K
karol288
17 Jan 2025
The time of free fall can be calculated:
t=square root(2h/g)
g=10 m/s^2
t = sq.root(2*10/10) = sq.root(2) = 1,41 seconds
t=square root(2h/g)
g=10 m/s^2
t = sq.root(2*10/10) = sq.root(2) = 1,41 seconds
E
Eddz25
23 May 2025
use velocity formula, s-ut + 1/2 at(2)
E
Eddz25
23 May 2025
s=ut + 1/2 at(2)
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