In a parallel LCR circuit, if the capacitance is increased by 4 times, what happens to the impedance of the capacitor?
- Increases by 4 times.
- Remains the same.
- Decreases by 75%.
Explanation
The reactance of the capacitor is 1 / (2 x pi x f x C), so increasing the capacitance by four times reduces that reactance to one quarter of its original value, a decrease of 75%. The capacitive opposition falls rather than rising or staying the same.
Jordi asking:
why is this happening?
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