The secondary winding of a transformer has an impedance of 10 ohms and 1500 turns. For the primary winding to have an impedance of 1 kilohm, how many turns must it have?
- 15,000.
- 1,500,000.
- 150,000
Explanation
Impedance reflects as the square of the turns ratio, so Np/Ns equals the square root of Zp/Zs. That is the square root of 1000/10, which is the square root of 100, equal to 10. The primary turns are therefore 10 x 1500 = 15,000. Squaring rather than rooting the ratio gives the incorrect larger figures.
Jordi asking:
why
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