PART66 Licensing Info
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• Licence Categories
• Modularization
• Number of questions
• Experience requirements
• Licence extension
Last comments in Q&A
krishnavikash left comment on Richiegeee's question:
its area is calculated by 1/2 * sum of parallel sides * perpendicular distance between them
its area is calculated by 1/2 * sum of parallel sides * perpendicular distance between them
Sina left comment on Richiegeee's question:
(2x)^2 * (z)^2 * (3x - z^2 ) =
4x^2 * z^2 * (3x-z^2) = {(4x^2 * z^2)*(3x) - (4x^2 * z^2)*(-z^2)} =
12x^3 * z^2 - 4x^2 * z4
Thus; (12x^3*z^2 - 4x^2*z4) / 2 ==> 6x^3 * z^2 - 2x^2 * z^4
(2x)^2 * (z)^2 * (3x - z^2 ) =
4x^2 * z^2 * (3x-z^2) = {(4x^2 * z^2)*(3x) - (4x^2 * z^2)*(-z^2)} =
12x^3 * z^2 - 4x^2 * z4
Thus; (12x^3*z^2 - 4x^2*z4) / 2 ==> 6x^3 * z^2 - 2x^2 * z^4
Sina left comment on Richiegeee's question:
A simple two gear system consists of two gears. Typically one gear is smaller while the other is larger. The smaller gear is normally called the pinion, while the larger gear is called the spur gear. Gear teeth are cut parallel to the shaft.
A simple two gear system consists of two gears. Typically one gear is smaller while the other is larger. The smaller gear is normally called the pinion, while the larger gear is called the spur gear. Gear teeth are cut parallel to the shaft.
joselizardo left comment on Benny's question:
4800/1200= 4
Z2=1000
4=(1000/Z1)^1/2
4^2 =1000/Z1
Z1=1000/16 = 62.5
WHY 16KOhm?
4800/1200= 4
Z2=1000
4=(1000/Z1)^1/2
4^2 =1000/Z1
Z1=1000/16 = 62.5
WHY 16KOhm?
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